其中一个进程的%VSZ为125.7，甚为疑惑，查了下其算法

From BusyBox

top.c- /*

top.c: * %VSZ = s->vsz/MemTotal

top.c- */

vzs is the size of the virtual memory used by the process (from /proc/<pid>/stat). This can include uninitialized memory and memory shared with other processes, and is therefore largely useless to determine how much memory a process actually needs.

MemTotal is found in /proc/meminfo, and is basically how much RAM you have.

该进程的VSZ为311m,设备的内存大小为，相除之后，果然与125.7吻合，是为记录，备忘。